Implement echo bot

This demonstrates the full one-to-one chat message backend without the
need to implement the GUI.

1 files changed, 33 insertions, 5 deletions

diff --git a/xmpp/message.go b/xmpp/message.go
index 58dc657..ba60390 100644
--- a/xmpp/message.go
+++ b/xmpp/message.go
@@ -2,16 +2,44 @@ package xmpp
 
 import (
 	"log"
+	"encoding/xml"
+	"math/rand"
+	"fmt"
 )
 
 type message struct {
-	Type string `xml:"type,attr"`
-	From string `xml:"from,attr"`
-	Body string `xml:"body"`
+	XMLName xml.Name `xml:"jabber:client message"`
+	Type    string `xml:"type,attr,omitempty"`
+	Id      string `xml:"id,attr,omitempty"`
+	From    string `xml:"from,attr,omitempty"`
+	To      string `xml:"to,attr,omitempty"`
+	// FIXME The lang attribute should have the `xml` prefix for the standard
+	// XML namespace. There was no option found so far which allows this with
+	// the standard library XML implementation and the xml.Encoder.Encode(v
+	// any) function.
+	Lang    string `xml:"lang,attr,omitempty"`
+	Body    string `xml:"body,omitempty"`
 }
 
 func handleMessage(s *session, m message) {
-	if m.Type == "chat" {
-		log.Printf("Got message '%s' from '%s'.\n", m.Body, m.From)
+	if m.Type == "chat" && m.Body != "" {
+		reply := fmt.Sprintf("Got %s", m.Body)
+		err := s.sendMessage(reply, m.From)
+		if err != nil {
+			log.Printf("Could not send message: %v\n", err)
+		}
 	}
 }
+
+func (s *session) sendMessage(m,j string) error {
+	msg := message{
+		From: s.jid,
+		Id: fmt.Sprintf("%016x", rand.Uint64()),
+		To: j,
+		Type: "chat",
+		Lang: "en",
+		Body: m,
+	}
+
+	return s.tx.Encode(msg)
+}