Use one bidirectional channel for communication

1 files changed, 5 insertions, 7 deletions

diff --git a/limox.go b/limox.go
index 2dee767..6723745 100644
--- a/limox.go
+++ b/limox.go
@@ -27,8 +27,7 @@ type Limox struct {
 	JidEditor  widget.Editor
 	PwdEditor  widget.Editor
 	MainButton widget.Clickable
-	XmppEvents chan any
-	GuiEvents  chan xmpp.Event
+	XmppConn chan any
 	State      LimoxState
 	Window     *app.Window
 	Operations op.Ops
@@ -43,8 +42,7 @@ func NewLimox() Limox {
 		),
 		Operations: op.Ops{},
 		Theme:      material.NewTheme(gofont.Collection()),
-		XmppEvents: make(chan any),
-		GuiEvents:  make(chan xmpp.Event),
+		XmppConn:   make(chan any),
 		State:      Disconnected,
 	}
 }
@@ -62,7 +60,7 @@ func (l *Limox) run() error {
 				}
 				l.draw(e)
 			}
-		case ev := <-l.XmppEvents:
+		case ev := <-l.XmppConn:
 			switch ev.(type) {
 			case error:
 				log.Print(ev)
@@ -88,14 +86,14 @@ func (l *Limox) buttonCallback() {
 	switch l.State {
 	case Disconnected:
 		log.Println("Starting connection establishment ...")
-		go xmpp.Run(l.GuiEvents, l.XmppEvents, l.JidEditor.Text(), l.PwdEditor.Text())
+		go xmpp.Run(l.XmppConn, l.JidEditor.Text(), l.PwdEditor.Text())
 		l.State = Connecting
 	case Connecting:
 		log.Println("Aborted connection establishment")
 		l.State = Disconnected
 	case Connected:
 		log.Println("Disconnecting ...")
-		l.GuiEvents <- xmpp.ShouldDisconnectEvent
+		l.XmppConn <- xmpp.ShouldDisconnectEvent
 		l.State = Disconnected
 	}
 }